3.1.40 \(\int \frac {1}{(e \cot (c+d x))^{5/2} (a+a \cot (c+d x))^3} \, dx\) [40]

3.1.40.1 Optimal result
3.1.40.2 Mathematica [C] (verified)
3.1.40.3 Rubi [A] (warning: unable to verify)
3.1.40.4 Maple [B] (verified)
3.1.40.5 Fricas [A] (verification not implemented)
3.1.40.6 Sympy [F]
3.1.40.7 Maxima [F(-2)]
3.1.40.8 Giac [F]
3.1.40.9 Mupad [B] (verification not implemented)

3.1.40.1 Optimal result

Integrand size = 25, antiderivative size = 215 \[ \int \frac {1}{(e \cot (c+d x))^{5/2} (a+a \cot (c+d x))^3} \, dx=-\frac {59 \arctan \left (\frac {\sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{8 a^3 d e^{5/2}}+\frac {\arctan \left (\frac {\sqrt {e}-\sqrt {e} \cot (c+d x)}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{2 \sqrt {2} a^3 d e^{5/2}}+\frac {55}{24 a^3 d e (e \cot (c+d x))^{3/2}}-\frac {63}{8 a^3 d e^2 \sqrt {e \cot (c+d x)}}-\frac {11}{8 a^3 d e (e \cot (c+d x))^{3/2} (1+\cot (c+d x))}-\frac {1}{4 a d e (e \cot (c+d x))^{3/2} (a+a \cot (c+d x))^2} \]

output
-59/8*arctan((e*cot(d*x+c))^(1/2)/e^(1/2))/a^3/d/e^(5/2)+55/24/a^3/d/e/(e* 
cot(d*x+c))^(3/2)-11/8/a^3/d/e/(e*cot(d*x+c))^(3/2)/(1+cot(d*x+c))-1/4/a/d 
/e/(e*cot(d*x+c))^(3/2)/(a+a*cot(d*x+c))^2+1/4*arctan(1/2*(e^(1/2)-cot(d*x 
+c)*e^(1/2))*2^(1/2)/(e*cot(d*x+c))^(1/2))/a^3/d/e^(5/2)*2^(1/2)-63/8/a^3/ 
d/e^2/(e*cot(d*x+c))^(1/2)
 
3.1.40.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 1.11 (sec) , antiderivative size = 124, normalized size of antiderivative = 0.58 \[ \int \frac {1}{(e \cot (c+d x))^{5/2} (a+a \cot (c+d x))^3} \, dx=\frac {\operatorname {Hypergeometric2F1}\left (-\frac {3}{2},1,-\frac {1}{2},-\cot (c+d x)\right )+2 \operatorname {Hypergeometric2F1}\left (-\frac {3}{2},2,-\frac {1}{2},-\cot (c+d x)\right )+2 \operatorname {Hypergeometric2F1}\left (-\frac {3}{2},3,-\frac {1}{2},-\cot (c+d x)\right )-\operatorname {Hypergeometric2F1}\left (-\frac {3}{4},1,\frac {1}{4},-\cot ^2(c+d x)\right )-3 \cot (c+d x) \operatorname {Hypergeometric2F1}\left (-\frac {1}{4},1,\frac {3}{4},-\cot ^2(c+d x)\right )}{6 a^3 d e (e \cot (c+d x))^{3/2}} \]

input
Integrate[1/((e*Cot[c + d*x])^(5/2)*(a + a*Cot[c + d*x])^3),x]
 
output
(Hypergeometric2F1[-3/2, 1, -1/2, -Cot[c + d*x]] + 2*Hypergeometric2F1[-3/ 
2, 2, -1/2, -Cot[c + d*x]] + 2*Hypergeometric2F1[-3/2, 3, -1/2, -Cot[c + d 
*x]] - Hypergeometric2F1[-3/4, 1, 1/4, -Cot[c + d*x]^2] - 3*Cot[c + d*x]*H 
ypergeometric2F1[-1/4, 1, 3/4, -Cot[c + d*x]^2])/(6*a^3*d*e*(e*Cot[c + d*x 
])^(3/2))
 
3.1.40.3 Rubi [A] (warning: unable to verify)

Time = 2.10 (sec) , antiderivative size = 244, normalized size of antiderivative = 1.13, number of steps used = 23, number of rules used = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.880, Rules used = {3042, 4052, 27, 3042, 4132, 25, 3042, 4132, 27, 3042, 4133, 27, 3042, 4136, 27, 3042, 4015, 218, 4117, 27, 73, 216}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{(a \cot (c+d x)+a)^3 (e \cot (c+d x))^{5/2}} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {1}{\left (a-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )^3 \left (-e \tan \left (c+d x+\frac {\pi }{2}\right )\right )^{5/2}}dx\)

\(\Big \downarrow \) 4052

\(\displaystyle -\frac {\int -\frac {7 e \cot ^2(c+d x) a^2+11 e a^2-4 e \cot (c+d x) a^2}{2 (e \cot (c+d x))^{5/2} (\cot (c+d x) a+a)^2}dx}{4 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \frac {7 e \cot ^2(c+d x) a^2+11 e a^2-4 e \cot (c+d x) a^2}{(e \cot (c+d x))^{5/2} (\cot (c+d x) a+a)^2}dx}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \frac {7 e \tan \left (c+d x+\frac {\pi }{2}\right )^2 a^2+11 e a^2+4 e \tan \left (c+d x+\frac {\pi }{2}\right ) a^2}{\left (-e \tan \left (c+d x+\frac {\pi }{2}\right )\right )^{5/2} \left (a-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )^2}dx}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 4132

\(\displaystyle \frac {-\frac {\int -\frac {55 e^2 a^4+55 e^2 \cot ^2(c+d x) a^4-8 e^2 \cot (c+d x) a^4}{(e \cot (c+d x))^{5/2} (\cot (c+d x) a+a)}dx}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {\frac {\int \frac {55 e^2 a^4+55 e^2 \cot ^2(c+d x) a^4-8 e^2 \cot (c+d x) a^4}{(e \cot (c+d x))^{5/2} (\cot (c+d x) a+a)}dx}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\int \frac {55 e^2 a^4+55 e^2 \tan \left (c+d x+\frac {\pi }{2}\right )^2 a^4+8 e^2 \tan \left (c+d x+\frac {\pi }{2}\right ) a^4}{\left (-e \tan \left (c+d x+\frac {\pi }{2}\right )\right )^{5/2} \left (a-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 4132

\(\displaystyle \frac {\frac {\frac {2 \int -\frac {3 \left (63 e^4 a^5+55 e^4 \cot ^2(c+d x) a^5\right )}{2 (e \cot (c+d x))^{3/2} (\cot (c+d x) a+a)}dx}{3 a e^3}+\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\int \frac {63 e^4 a^5+55 e^4 \cot ^2(c+d x) a^5}{(e \cot (c+d x))^{3/2} (\cot (c+d x) a+a)}dx}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\int \frac {63 e^4 a^5+55 e^4 \tan \left (c+d x+\frac {\pi }{2}\right )^2 a^5}{\left (-e \tan \left (c+d x+\frac {\pi }{2}\right )\right )^{3/2} \left (a-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 4133

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {2 \int -\frac {63 a^6 e^6+63 a^6 \cot ^2(c+d x) e^6+8 a^6 \cot (c+d x) e^6}{2 \sqrt {e \cot (c+d x)} (\cot (c+d x) a+a)}dx}{a e^3}+\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {\int \frac {63 a^6 e^6+63 a^6 \cot ^2(c+d x) e^6+8 a^6 \cot (c+d x) e^6}{\sqrt {e \cot (c+d x)} (\cot (c+d x) a+a)}dx}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {\int \frac {63 a^6 e^6+63 a^6 \tan \left (c+d x+\frac {\pi }{2}\right )^2 e^6-8 a^6 \tan \left (c+d x+\frac {\pi }{2}\right ) e^6}{\sqrt {-e \tan \left (c+d x+\frac {\pi }{2}\right )} \left (a-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 4136

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {59 a^6 e^6 \int \frac {\cot ^2(c+d x)+1}{\sqrt {e \cot (c+d x)} (\cot (c+d x) a+a)}dx+\frac {\int \frac {8 \left (e^6 a^7+e^6 \cot (c+d x) a^7\right )}{\sqrt {e \cot (c+d x)}}dx}{2 a^2}}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {59 a^6 e^6 \int \frac {\cot ^2(c+d x)+1}{\sqrt {e \cot (c+d x)} (\cot (c+d x) a+a)}dx+\frac {4 \int \frac {e^6 a^7+e^6 \cot (c+d x) a^7}{\sqrt {e \cot (c+d x)}}dx}{a^2}}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {59 a^6 e^6 \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-e \tan \left (c+d x+\frac {\pi }{2}\right )} \left (a-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx+\frac {4 \int \frac {a^7 e^6-a^7 e^6 \tan \left (c+d x+\frac {\pi }{2}\right )}{\sqrt {-e \tan \left (c+d x+\frac {\pi }{2}\right )}}dx}{a^2}}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 4015

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {59 a^6 e^6 \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-e \tan \left (c+d x+\frac {\pi }{2}\right )} \left (a-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx-\frac {8 a^{12} e^{12} \int \frac {1}{-2 e^{12} a^{14}-\left (a^7 e^6-a^7 e^6 \cot (c+d x)\right )^2 \tan (c+d x)}d\frac {a^7 e^6-a^7 e^6 \cot (c+d x)}{\sqrt {e \cot (c+d x)}}}{d}}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 218

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {59 a^6 e^6 \int \frac {\tan \left (c+d x+\frac {\pi }{2}\right )^2+1}{\sqrt {-e \tan \left (c+d x+\frac {\pi }{2}\right )} \left (a-a \tan \left (c+d x+\frac {\pi }{2}\right )\right )}dx+\frac {4 \sqrt {2} a^5 e^{11/2} \arctan \left (\frac {a^7 e^6-a^7 e^6 \cot (c+d x)}{\sqrt {2} a^7 e^{11/2} \sqrt {e \cot (c+d x)}}\right )}{d}}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 4117

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {\frac {59 a^6 e^6 \int \frac {1}{a \sqrt {e \cot (c+d x)} (\cot (c+d x)+1)}d(-\cot (c+d x))}{d}+\frac {4 \sqrt {2} a^5 e^{11/2} \arctan \left (\frac {a^7 e^6-a^7 e^6 \cot (c+d x)}{\sqrt {2} a^7 e^{11/2} \sqrt {e \cot (c+d x)}}\right )}{d}}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {\frac {59 a^5 e^6 \int \frac {1}{\sqrt {e \cot (c+d x)} (\cot (c+d x)+1)}d(-\cot (c+d x))}{d}+\frac {4 \sqrt {2} a^5 e^{11/2} \arctan \left (\frac {a^7 e^6-a^7 e^6 \cot (c+d x)}{\sqrt {2} a^7 e^{11/2} \sqrt {e \cot (c+d x)}}\right )}{d}}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 73

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {\frac {4 \sqrt {2} a^5 e^{11/2} \arctan \left (\frac {a^7 e^6-a^7 e^6 \cot (c+d x)}{\sqrt {2} a^7 e^{11/2} \sqrt {e \cot (c+d x)}}\right )}{d}-\frac {118 a^5 e^5 \int \frac {1}{\frac {\cot ^2(c+d x)}{e}+1}d\sqrt {e \cot (c+d x)}}{d}}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

\(\Big \downarrow \) 216

\(\displaystyle \frac {\frac {\frac {110 a^3 e}{3 d (e \cot (c+d x))^{3/2}}-\frac {\frac {126 a^4 e^3}{d \sqrt {e \cot (c+d x)}}-\frac {\frac {118 a^5 e^{11/2} \arctan \left (\frac {\cot (c+d x)}{\sqrt {e}}\right )}{d}+\frac {4 \sqrt {2} a^5 e^{11/2} \arctan \left (\frac {a^7 e^6-a^7 e^6 \cot (c+d x)}{\sqrt {2} a^7 e^{11/2} \sqrt {e \cot (c+d x)}}\right )}{d}}{a e^3}}{a e^3}}{2 a^3 e}-\frac {11}{d (\cot (c+d x)+1) (e \cot (c+d x))^{3/2}}}{8 a^3 e}-\frac {1}{4 a d e (a \cot (c+d x)+a)^2 (e \cot (c+d x))^{3/2}}\)

input
Int[1/((e*Cot[c + d*x])^(5/2)*(a + a*Cot[c + d*x])^3),x]
 
output
-1/4*1/(a*d*e*(e*Cot[c + d*x])^(3/2)*(a + a*Cot[c + d*x])^2) + (-11/(d*(e* 
Cot[c + d*x])^(3/2)*(1 + Cot[c + d*x])) + ((110*a^3*e)/(3*d*(e*Cot[c + d*x 
])^(3/2)) - (-(((118*a^5*e^(11/2)*ArcTan[Cot[c + d*x]/Sqrt[e]])/d + (4*Sqr 
t[2]*a^5*e^(11/2)*ArcTan[(a^7*e^6 - a^7*e^6*Cot[c + d*x])/(Sqrt[2]*a^7*e^( 
11/2)*Sqrt[e*Cot[c + d*x]])])/d)/(a*e^3)) + (126*a^4*e^3)/(d*Sqrt[e*Cot[c 
+ d*x]]))/(a*e^3))/(2*a^3*e))/(8*a^3*e)
 

3.1.40.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 73
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 216
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*A 
rcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a 
, 0] || GtQ[b, 0])
 

rule 218
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R 
t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4015
Int[((c_) + (d_.)*tan[(e_.) + (f_.)*(x_)])/Sqrt[(b_.)*tan[(e_.) + (f_.)*(x_ 
)]], x_Symbol] :> Simp[-2*(d^2/f)   Subst[Int[1/(2*c*d + b*x^2), x], x, (c 
- d*Tan[e + f*x])/Sqrt[b*Tan[e + f*x]]], x] /; FreeQ[{b, c, d, e, f}, x] && 
 EqQ[c^2 - d^2, 0]
 

rule 4052
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + 
 (f_.)*(x_)])^(n_), x_Symbol] :> Simp[b^2*(a + b*Tan[e + f*x])^(m + 1)*((c 
+ d*Tan[e + f*x])^(n + 1)/(f*(m + 1)*(a^2 + b^2)*(b*c - a*d))), x] + Simp[1 
/((m + 1)*(a^2 + b^2)*(b*c - a*d))   Int[(a + b*Tan[e + f*x])^(m + 1)*(c + 
d*Tan[e + f*x])^n*Simp[a*(b*c - a*d)*(m + 1) - b^2*d*(m + n + 2) - b*(b*c - 
 a*d)*(m + 1)*Tan[e + f*x] - b^2*d*(m + n + 2)*Tan[e + f*x]^2, x], x], x] / 
; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] 
 && NeQ[c^2 + d^2, 0] && IntegerQ[2*m] && LtQ[m, -1] && (LtQ[n, 0] || Integ 
erQ[m]) &&  !(ILtQ[n, -1] && ( !IntegerQ[m] || (EqQ[c, 0] && NeQ[a, 0])))
 

rule 4117
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*tan[(e_.) 
+ (f_.)*(x_)])^(n_.)*((A_) + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> 
 Simp[A/f   Subst[Int[(a + b*x)^m*(c + d*x)^n, x], x, Tan[e + f*x]], x] /; 
FreeQ[{a, b, c, d, e, f, A, C, m, n}, x] && EqQ[A, C]
 

rule 4132
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + 
 (f_.)*(x_)])^(n_)*((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) 
 + (f_.)*(x_)]^2), x_Symbol] :> Simp[(A*b^2 - a*(b*B - a*C))*(a + b*Tan[e + 
 f*x])^(m + 1)*((c + d*Tan[e + f*x])^(n + 1)/(f*(m + 1)*(b*c - a*d)*(a^2 + 
b^2))), x] + Simp[1/((m + 1)*(b*c - a*d)*(a^2 + b^2))   Int[(a + b*Tan[e + 
f*x])^(m + 1)*(c + d*Tan[e + f*x])^n*Simp[A*(a*(b*c - a*d)*(m + 1) - b^2*d* 
(m + n + 2)) + (b*B - a*C)*(b*c*(m + 1) + a*d*(n + 1)) - (m + 1)*(b*c - a*d 
)*(A*b - a*B - b*C)*Tan[e + f*x] - d*(A*b^2 - a*(b*B - a*C))*(m + n + 2)*Ta 
n[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, n}, x] && NeQ 
[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0] && LtQ[m, -1] && 
!(ILtQ[n, -1] && ( !IntegerQ[m] || (EqQ[c, 0] && NeQ[a, 0])))
 

rule 4133
Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + 
 (f_.)*(x_)])^(n_)*((A_.) + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> 
Simp[(A*b^2 + a^2*C)*(a + b*Tan[e + f*x])^(m + 1)*((c + d*Tan[e + f*x])^(n 
+ 1)/(f*(m + 1)*(b*c - a*d)*(a^2 + b^2))), x] + Simp[1/((m + 1)*(b*c - a*d) 
*(a^2 + b^2))   Int[(a + b*Tan[e + f*x])^(m + 1)*(c + d*Tan[e + f*x])^n*Sim 
p[A*(a*(b*c - a*d)*(m + 1) - b^2*d*(m + n + 2)) - a*C*(b*c*(m + 1) + a*d*(n 
 + 1)) - (m + 1)*(b*c - a*d)*(A*b - b*C)*Tan[e + f*x] - d*(A*b^2 + a^2*C)*( 
m + n + 2)*Tan[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, C, n}, 
 x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0] && LtQ[m 
, -1] &&  !(ILtQ[n, -1] && ( !IntegerQ[m] || (EqQ[c, 0] && NeQ[a, 0])))
 

rule 4136
Int[(((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*tan[(e_.) 
+ (f_.)*(x_)] + (C_.)*tan[(e_.) + (f_.)*(x_)]^2))/((a_.) + (b_.)*tan[(e_.) 
+ (f_.)*(x_)]), x_Symbol] :> Simp[1/(a^2 + b^2)   Int[(c + d*Tan[e + f*x])^ 
n*Simp[b*B + a*(A - C) + (a*B - b*(A - C))*Tan[e + f*x], x], x], x] + Simp[ 
(A*b^2 - a*b*B + a^2*C)/(a^2 + b^2)   Int[(c + d*Tan[e + f*x])^n*((1 + Tan[ 
e + f*x]^2)/(a + b*Tan[e + f*x])), x], x] /; FreeQ[{a, b, c, d, e, f, A, B, 
 C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0] & 
&  !GtQ[n, 0] &&  !LeQ[n, -1]
 
3.1.40.4 Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(378\) vs. \(2(178)=356\).

Time = 0.05 (sec) , antiderivative size = 379, normalized size of antiderivative = 1.76

method result size
derivativedivides \(-\frac {2 e^{4} \left (\frac {\frac {\left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 e}+\frac {\sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 \left (e^{2}\right )^{\frac {1}{4}}}}{4 e^{6}}-\frac {1}{3 e^{5} \left (e \cot \left (d x +c \right )\right )^{\frac {3}{2}}}+\frac {3}{e^{6} \sqrt {e \cot \left (d x +c \right )}}+\frac {\frac {\frac {15 \left (e \cot \left (d x +c \right )\right )^{\frac {3}{2}}}{4}+\frac {17 e \sqrt {e \cot \left (d x +c \right )}}{4}}{\left (e \cot \left (d x +c \right )+e \right )^{2}}+\frac {59 \arctan \left (\frac {\sqrt {e \cot \left (d x +c \right )}}{\sqrt {e}}\right )}{4 \sqrt {e}}}{4 e^{6}}\right )}{d \,a^{3}}\) \(379\)
default \(-\frac {2 e^{4} \left (\frac {\frac {\left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 e}+\frac {\sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 \left (e^{2}\right )^{\frac {1}{4}}}}{4 e^{6}}-\frac {1}{3 e^{5} \left (e \cot \left (d x +c \right )\right )^{\frac {3}{2}}}+\frac {3}{e^{6} \sqrt {e \cot \left (d x +c \right )}}+\frac {\frac {\frac {15 \left (e \cot \left (d x +c \right )\right )^{\frac {3}{2}}}{4}+\frac {17 e \sqrt {e \cot \left (d x +c \right )}}{4}}{\left (e \cot \left (d x +c \right )+e \right )^{2}}+\frac {59 \arctan \left (\frac {\sqrt {e \cot \left (d x +c \right )}}{\sqrt {e}}\right )}{4 \sqrt {e}}}{4 e^{6}}\right )}{d \,a^{3}}\) \(379\)

input
int(1/(e*cot(d*x+c))^(5/2)/(a+a*cot(d*x+c))^3,x,method=_RETURNVERBOSE)
 
output
-2/d/a^3*e^4*(1/4/e^6*(1/8/e*(e^2)^(1/4)*2^(1/2)*(ln((e*cot(d*x+c)+(e^2)^( 
1/4)*(e*cot(d*x+c))^(1/2)*2^(1/2)+(e^2)^(1/2))/(e*cot(d*x+c)-(e^2)^(1/4)*( 
e*cot(d*x+c))^(1/2)*2^(1/2)+(e^2)^(1/2)))+2*arctan(2^(1/2)/(e^2)^(1/4)*(e* 
cot(d*x+c))^(1/2)+1)-2*arctan(-2^(1/2)/(e^2)^(1/4)*(e*cot(d*x+c))^(1/2)+1) 
)+1/8/(e^2)^(1/4)*2^(1/2)*(ln((e*cot(d*x+c)-(e^2)^(1/4)*(e*cot(d*x+c))^(1/ 
2)*2^(1/2)+(e^2)^(1/2))/(e*cot(d*x+c)+(e^2)^(1/4)*(e*cot(d*x+c))^(1/2)*2^( 
1/2)+(e^2)^(1/2)))+2*arctan(2^(1/2)/(e^2)^(1/4)*(e*cot(d*x+c))^(1/2)+1)-2* 
arctan(-2^(1/2)/(e^2)^(1/4)*(e*cot(d*x+c))^(1/2)+1)))-1/3/e^5/(e*cot(d*x+c 
))^(3/2)+3/e^6/(e*cot(d*x+c))^(1/2)+1/4/e^6*((15/4*(e*cot(d*x+c))^(3/2)+17 
/4*e*(e*cot(d*x+c))^(1/2))/(e*cot(d*x+c)+e)^2+59/4/e^(1/2)*arctan((e*cot(d 
*x+c))^(1/2)/e^(1/2))))
 
3.1.40.5 Fricas [A] (verification not implemented)

Time = 0.30 (sec) , antiderivative size = 718, normalized size of antiderivative = 3.34 \[ \int \frac {1}{(e \cot (c+d x))^{5/2} (a+a \cot (c+d x))^3} \, dx=\left [-\frac {6 \, \sqrt {2} {\left ({\left (\cos \left (2 \, d x + 2 \, c\right ) + 1\right )} \sin \left (2 \, d x + 2 \, c\right ) + \cos \left (2 \, d x + 2 \, c\right ) + 1\right )} \sqrt {-e} \log \left (\sqrt {2} \sqrt {-e} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} {\left (\cos \left (2 \, d x + 2 \, c\right ) + \sin \left (2 \, d x + 2 \, c\right ) - 1\right )} - 2 \, e \sin \left (2 \, d x + 2 \, c\right ) + e\right ) + 177 \, {\left ({\left (\cos \left (2 \, d x + 2 \, c\right ) + 1\right )} \sin \left (2 \, d x + 2 \, c\right ) + \cos \left (2 \, d x + 2 \, c\right ) + 1\right )} \sqrt {-e} \log \left (\frac {e \cos \left (2 \, d x + 2 \, c\right ) - e \sin \left (2 \, d x + 2 \, c\right ) + 2 \, \sqrt {-e} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} \sin \left (2 \, d x + 2 \, c\right ) + e}{\cos \left (2 \, d x + 2 \, c\right ) + \sin \left (2 \, d x + 2 \, c\right ) + 1}\right ) - {\left (339 \, \cos \left (2 \, d x + 2 \, c\right )^{2} - 7 \, {\left (11 \, \cos \left (2 \, d x + 2 \, c\right ) + 43\right )} \sin \left (2 \, d x + 2 \, c\right ) - 32 \, \cos \left (2 \, d x + 2 \, c\right ) - 307\right )} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}}}{48 \, {\left (a^{3} d e^{3} \cos \left (2 \, d x + 2 \, c\right ) + a^{3} d e^{3} + {\left (a^{3} d e^{3} \cos \left (2 \, d x + 2 \, c\right ) + a^{3} d e^{3}\right )} \sin \left (2 \, d x + 2 \, c\right )\right )}}, \frac {12 \, \sqrt {2} {\left ({\left (\cos \left (2 \, d x + 2 \, c\right ) + 1\right )} \sin \left (2 \, d x + 2 \, c\right ) + \cos \left (2 \, d x + 2 \, c\right ) + 1\right )} \sqrt {e} \arctan \left (-\frac {\sqrt {2} \sqrt {e} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} {\left (\cos \left (2 \, d x + 2 \, c\right ) - \sin \left (2 \, d x + 2 \, c\right ) + 1\right )}}{2 \, {\left (e \cos \left (2 \, d x + 2 \, c\right ) + e\right )}}\right ) - 354 \, {\left ({\left (\cos \left (2 \, d x + 2 \, c\right ) + 1\right )} \sin \left (2 \, d x + 2 \, c\right ) + \cos \left (2 \, d x + 2 \, c\right ) + 1\right )} \sqrt {e} \arctan \left (\frac {\sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}}}{\sqrt {e}}\right ) + {\left (339 \, \cos \left (2 \, d x + 2 \, c\right )^{2} - 7 \, {\left (11 \, \cos \left (2 \, d x + 2 \, c\right ) + 43\right )} \sin \left (2 \, d x + 2 \, c\right ) - 32 \, \cos \left (2 \, d x + 2 \, c\right ) - 307\right )} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}}}{48 \, {\left (a^{3} d e^{3} \cos \left (2 \, d x + 2 \, c\right ) + a^{3} d e^{3} + {\left (a^{3} d e^{3} \cos \left (2 \, d x + 2 \, c\right ) + a^{3} d e^{3}\right )} \sin \left (2 \, d x + 2 \, c\right )\right )}}\right ] \]

input
integrate(1/(e*cot(d*x+c))^(5/2)/(a+a*cot(d*x+c))^3,x, algorithm="fricas")
 
output
[-1/48*(6*sqrt(2)*((cos(2*d*x + 2*c) + 1)*sin(2*d*x + 2*c) + cos(2*d*x + 2 
*c) + 1)*sqrt(-e)*log(sqrt(2)*sqrt(-e)*sqrt((e*cos(2*d*x + 2*c) + e)/sin(2 
*d*x + 2*c))*(cos(2*d*x + 2*c) + sin(2*d*x + 2*c) - 1) - 2*e*sin(2*d*x + 2 
*c) + e) + 177*((cos(2*d*x + 2*c) + 1)*sin(2*d*x + 2*c) + cos(2*d*x + 2*c) 
 + 1)*sqrt(-e)*log((e*cos(2*d*x + 2*c) - e*sin(2*d*x + 2*c) + 2*sqrt(-e)*s 
qrt((e*cos(2*d*x + 2*c) + e)/sin(2*d*x + 2*c))*sin(2*d*x + 2*c) + e)/(cos( 
2*d*x + 2*c) + sin(2*d*x + 2*c) + 1)) - (339*cos(2*d*x + 2*c)^2 - 7*(11*co 
s(2*d*x + 2*c) + 43)*sin(2*d*x + 2*c) - 32*cos(2*d*x + 2*c) - 307)*sqrt((e 
*cos(2*d*x + 2*c) + e)/sin(2*d*x + 2*c)))/(a^3*d*e^3*cos(2*d*x + 2*c) + a^ 
3*d*e^3 + (a^3*d*e^3*cos(2*d*x + 2*c) + a^3*d*e^3)*sin(2*d*x + 2*c)), 1/48 
*(12*sqrt(2)*((cos(2*d*x + 2*c) + 1)*sin(2*d*x + 2*c) + cos(2*d*x + 2*c) + 
 1)*sqrt(e)*arctan(-1/2*sqrt(2)*sqrt(e)*sqrt((e*cos(2*d*x + 2*c) + e)/sin( 
2*d*x + 2*c))*(cos(2*d*x + 2*c) - sin(2*d*x + 2*c) + 1)/(e*cos(2*d*x + 2*c 
) + e)) - 354*((cos(2*d*x + 2*c) + 1)*sin(2*d*x + 2*c) + cos(2*d*x + 2*c) 
+ 1)*sqrt(e)*arctan(sqrt((e*cos(2*d*x + 2*c) + e)/sin(2*d*x + 2*c))/sqrt(e 
)) + (339*cos(2*d*x + 2*c)^2 - 7*(11*cos(2*d*x + 2*c) + 43)*sin(2*d*x + 2* 
c) - 32*cos(2*d*x + 2*c) - 307)*sqrt((e*cos(2*d*x + 2*c) + e)/sin(2*d*x + 
2*c)))/(a^3*d*e^3*cos(2*d*x + 2*c) + a^3*d*e^3 + (a^3*d*e^3*cos(2*d*x + 2* 
c) + a^3*d*e^3)*sin(2*d*x + 2*c))]
 
3.1.40.6 Sympy [F]

\[ \int \frac {1}{(e \cot (c+d x))^{5/2} (a+a \cot (c+d x))^3} \, dx=\frac {\int \frac {1}{\left (e \cot {\left (c + d x \right )}\right )^{\frac {5}{2}} \cot ^{3}{\left (c + d x \right )} + 3 \left (e \cot {\left (c + d x \right )}\right )^{\frac {5}{2}} \cot ^{2}{\left (c + d x \right )} + 3 \left (e \cot {\left (c + d x \right )}\right )^{\frac {5}{2}} \cot {\left (c + d x \right )} + \left (e \cot {\left (c + d x \right )}\right )^{\frac {5}{2}}}\, dx}{a^{3}} \]

input
integrate(1/(e*cot(d*x+c))**(5/2)/(a+a*cot(d*x+c))**3,x)
 
output
Integral(1/((e*cot(c + d*x))**(5/2)*cot(c + d*x)**3 + 3*(e*cot(c + d*x))** 
(5/2)*cot(c + d*x)**2 + 3*(e*cot(c + d*x))**(5/2)*cot(c + d*x) + (e*cot(c 
+ d*x))**(5/2)), x)/a**3
 
3.1.40.7 Maxima [F(-2)]

Exception generated. \[ \int \frac {1}{(e \cot (c+d x))^{5/2} (a+a \cot (c+d x))^3} \, dx=\text {Exception raised: ValueError} \]

input
integrate(1/(e*cot(d*x+c))^(5/2)/(a+a*cot(d*x+c))^3,x, algorithm="maxima")
 
output
Exception raised: ValueError >> Computation failed since Maxima requested 
additional constraints; using the 'assume' command before evaluation *may* 
 help (example of legal syntax is 'assume(e>0)', see `assume?` for more de 
tails)Is e
 
3.1.40.8 Giac [F]

\[ \int \frac {1}{(e \cot (c+d x))^{5/2} (a+a \cot (c+d x))^3} \, dx=\int { \frac {1}{{\left (a \cot \left (d x + c\right ) + a\right )}^{3} \left (e \cot \left (d x + c\right )\right )^{\frac {5}{2}}} \,d x } \]

input
integrate(1/(e*cot(d*x+c))^(5/2)/(a+a*cot(d*x+c))^3,x, algorithm="giac")
 
output
integrate(1/((a*cot(d*x + c) + a)^3*(e*cot(d*x + c))^(5/2)), x)
 
3.1.40.9 Mupad [B] (verification not implemented)

Time = 13.53 (sec) , antiderivative size = 193, normalized size of antiderivative = 0.90 \[ \int \frac {1}{(e \cot (c+d x))^{5/2} (a+a \cot (c+d x))^3} \, dx=-\frac {\frac {63\,e\,{\mathrm {cot}\left (c+d\,x\right )}^3}{8}+\frac {323\,e\,{\mathrm {cot}\left (c+d\,x\right )}^2}{24}+\frac {14\,e\,\mathrm {cot}\left (c+d\,x\right )}{3}-\frac {2\,e}{3}}{a^3\,d\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{7/2}+2\,a^3\,d\,e\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{5/2}+a^3\,d\,e^2\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{3/2}}-\frac {59\,\mathrm {atan}\left (\frac {\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{\sqrt {e}}\right )}{8\,a^3\,d\,e^{5/2}}-\frac {\sqrt {2}\,\left (2\,\mathrm {atan}\left (\frac {\sqrt {2}\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{2\,\sqrt {e}}\right )+2\,\mathrm {atan}\left (\frac {\sqrt {2}\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{2\,\sqrt {e}}+\frac {\sqrt {2}\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{3/2}}{2\,e^{3/2}}\right )\right )}{8\,a^3\,d\,e^{5/2}} \]

input
int(1/((e*cot(c + d*x))^(5/2)*(a + a*cot(c + d*x))^3),x)
 
output
- ((14*e*cot(c + d*x))/3 - (2*e)/3 + (323*e*cot(c + d*x)^2)/24 + (63*e*cot 
(c + d*x)^3)/8)/(a^3*d*(e*cot(c + d*x))^(7/2) + 2*a^3*d*e*(e*cot(c + d*x)) 
^(5/2) + a^3*d*e^2*(e*cot(c + d*x))^(3/2)) - (59*atan((e*cot(c + d*x))^(1/ 
2)/e^(1/2)))/(8*a^3*d*e^(5/2)) - (2^(1/2)*(2*atan((2^(1/2)*(e*cot(c + d*x) 
)^(1/2))/(2*e^(1/2))) + 2*atan((2^(1/2)*(e*cot(c + d*x))^(1/2))/(2*e^(1/2) 
) + (2^(1/2)*(e*cot(c + d*x))^(3/2))/(2*e^(3/2)))))/(8*a^3*d*e^(5/2))